Maximum Area problem solved with derivative

Max Area Solution

Find x value relative to radius r. x = $\frac{440 - 2 π r}{2}$ x = 220 - π r Area of rectangular section A(r) = x 2r* Substitute x = 220 - π r A(r) = (220 - π r) * 2r A(r) = 440r - 2 π r² Take derivative. Solve or r. 0 = 440 - 4 π r 440 = 4 π r r = $\frac{110}{π}$ Substitute r = $\frac{110}{π}$ into equation above x = 220 - π r x = 220 - π ( $\frac{110}{π}$ ) = 110 Maximum dimensions are: x 2r =* 110 by $\frac{220}{π}$
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Max Area Solution